I'm trying to figure out how to get the angle of a superclass inside the subclass but I need the value to be updated constantly as the superclass also turns constantly so the angle is always changing. Any way to do this?
ckverdad wrote ...
2019/4/12
getRotation() value
Just use the getRotation method. It always returns the current rotation of the actor. Btw, there is no such thing as a rotation of a superclass -- or any class, for that matter. What you mean is: the rotation of an Actor object; or of an instance of type Actor. An instance of any class is also an instance of all its superclasses.
Sorry for the confusion. What I meant was how do I call the variable offsetX that is present in the superclass A, in it's subclass B?
and
With this code, the console would always output 0, though if offsetX is printed within the superclass, A, it would output the correct angles.
public class A extends Actor
{
int offsetX = 0;
public void act()
{
turn(-2);
offsetX = (-(getRotation() - 360));
}
}public class B extends A
{
public void act()
{
System.out.println(super.offsetX);
}
}
ckverdad wrote...
Still produces an output 0 :/
You need to understand the difference between an object and a class. If you have two different objects in your world, one is of class A (and B) and the other one is only of class B, then no, you can't get the rotation of the other one directly like this. Every object of class A and every object of class B will have their own offsetX variable. You need to get a reference to the object and get the current value of the variable.
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