i have a fish object that i want to remove and then add a new fish object when i clik the object whit the mouse i have tryed different ways but cant work it out so ill be glad if someone culd help me out :-)
vbh wrote ...
2013/10/22
remove object and add a new on mouseclicked
If I understood you correctly you want to remove your fish if you click on it and add a new one.
To do this you need to check whether the fish was clicked like this:
//in your fish class;
public void act() {
if (Greenfoot.mouseClicked(this)) {
getWorld().addObject(new Fish(), Greenfoot.getRandomNumber(getWorld().getWidth()), Greenfoot.getRandomNumber(getWorld().getHeight()));//add a new fish at a random position;
getWorld().removeObject(this);
return;
}
}Hi again
the code above does the trick whit removing and adding a new object, but sometimes the new fish object isnt showing in world any suggestion to way???
i have tryed to change the code to
public void act()
{ if (Greenfoot.mouseClicked(this))
{ getWorld().addObject(new Fish(), Greenfoot.getRandomNumber(500)<10), Greenfoot.getRandomNumber(400)<10);
getWorld().removeObject(this);
return; }
}
in hope that it would secure that the object is inside the world but i get an erro
Please use code tags for code in messages.
You have:
What is the '< 10' for? (It is what is causing the error).
getWorld().addObject(new Fish(), Greenfoot.getRandomNumber(500)<10), Greenfoot.getRandomNumber(400)<10);
If the width of your world is 500 and you do not want to spawn within 10 of either side, then the range of x for spawning will be 480 (500 - 10 - 10 . This range value is what you should use as the 'getRandomNumber' argument; and since the first x allowable is at 10, just add that to the number returned from the random call.
It would be similar for the y coordinate.
int x = Greenfoot.getRandomNumber(480)+10;
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