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RedCreeper
RedCreeper wrote ...

2013/10/26

odd or even number

RedCreeper RedCreeper

2013/10/26

#
I need a way to tell if a in variable is an odd or even number, and then if it is odd add one ,and if it is even minus one
bourne bourne

2013/10/26

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Use something like this:
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if (num % 2 == 0) // Even
{}
else // Odd
{}
danpost danpost

2013/10/26

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?
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var = var - 1 + 2 * var % 2;
RedCreeper RedCreeper

2013/10/26

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Danpost how does that decide weather it is odd or even
bourne bourne

2013/10/26

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var % 2 results as only 0 or 1 (0 for even, 1 for odd) He compacted your problem to a single statement
danpost danpost

2013/10/26

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The '- 1' adjusts the value as if it was even either way. The 'var % 2' returns the remainder of 'var / 2'; so, it returns '1' if odd or '0' if even. Multiplying that by 2 and adding will make the adjustment in the case that it is odd (and adjust by zero, or no additional change, in the case it is even).
RedCreeper RedCreeper

2013/10/26

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Would this work for a value of 35
danpost danpost

2013/10/26

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RedCreeper wrote...
Would this work for a value of 35
Yes. Negative numbers may not work the way you want, however.
RedCreeper RedCreeper

2013/10/26

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How do I make is that if it is odd in adds one from another variable, and if even subtract one from a different variable
danpost danpost

2013/10/26

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varA += var % 2;
varB -= (var + 1) % 2;
RedCreeper RedCreeper

2013/10/26

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thank you
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